Calculus/Calculus

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Question
1.I am integrating sqrt(x^2+a^2) by parts,but I came to the point when I have find the derivative of sqrt(x^2+a^2),and I don't know what to do and which formula to use pls help me.
2.I have to find the integral of (2x+a)/sqrt(x^2+ax),i just don't know which formula to use as I am in earlier stage of calculating the integral of sqrt(a+x)/sqrtx and it is the part of this question.
3.I also want to find the derivative of asin^2(x)+bcos^2(x)


Answer
1. The problem needs to be integrated by a trig substitution.
Draw a right triangle with the far side x from the angle Θ and the near side a to the angle Θ.  Then tan(Θ)=x/a, or a*tan(Θ)=x.  The integral becomes a√(tan˛Θ+1) = a*sec(Θ) with the dx being asec˛(x).  In the end, you have the integral of a˛sec^3(Θ) dΘ.
Note that sec˛(Θ) = 1 + tan˛(Θ), so the problem is to integrate
a˛sec(Θ)(1+tan˛(Θ)).  Multiply this out and both expression can be integrated with basic trig identities of integration.

2. Let u=x˛+ax, then du=2x+a.  Do a u substitution in this way.

3. The derivative of any function squared, f˛(x), is 2f(x)f'(x).  This can be applied to sin˛(x) and cos˛(x).  Once this has been done, both terms will both involve a sin(x)cos(x) and can be combined.

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