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About Scotto
Expertise
Any kind of mathematics (calculus, analysis, game theory, linear approximation, finite differences, linear regression, linear programming, numerical analysis, probability, statistics, etc.). I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

Experience
Experience in the area: I have tutored students in all areas of mathematics for over 20 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

Publications
Maybe not a publication, but I have respond to well oveer 3000 questions on the PC. That's around 2,000 in basic math and 1,000 in advanced math.

Education/Credentials
I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

Awards and Honors
I have been nominated as the expert of the month several times. All of my scores right now are at least a 9.8 average (out of 10).

Past/Present Clients
My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you.

 
   

You are here:  Experts > Teens > Homework/Study Tips > Calculus > calculus

Calculus - calculus


Expert: Scotto - 7/8/2008

Question
i trying to find dx/dy of 2x^3 - 3x^2y + 2xy^2 - y^3 = 2
i came up with dx/dy = -6x^2 + 6xy - 2y^2/ -3x^2 + 4xy - 3y^2.......if this is the answer...can it be simplified and if so how

Answer
That answer is almost right except that it left out y' (dy/dx).

The derivatives of each of the terms is
6x², -6xy-3x²y', 2y²+4xyy', -3y²y', and 0.

We then have 6x² - 6xy - 3x²y' + 2y²+4xyy' - 3y²y' = 0.

Move the expressions without y' to the other side of the equation.

Factor out y' and divide both sides of the equation by the coefficient in front of y'.


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