AboutScotto Expertise Any kind of mathematics (calculus, analysis, game theory, linear approximation, finite differences, linear regression, linear programming, numerical analysis, probability, statistics, etc.).
I also have answered some questions in
Physics (mass, momentum, falling bodies),
Chemistry (charge, reactions, symbols, molecules), and
Biology.
Experience Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
Publications Maybe not a publication, but I have respond to well oveer 3000 questions on the PC.
That's around 2,000 in basic math and 1,000 in advanced math.
Education/Credentials I aquired well over 40 hours of upper division courses. This was well over the number that were required.
I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few junior level courses my sophomore year.
Awards and Honors I have been nominated as the expert of the month several times.
All of my scores right now are at least a 9.8 average (out of 10).
Past/Present Clients My past clients have been students at OSU, students at the college in South Seattle,
referals from a company, friends and aquantenances, people from my church, and people like you.
Question i trying to find dx/dy of 2x^3 - 3x^2y + 2xy^2 - y^3 = 2
i came up with dx/dy = -6x^2 + 6xy - 2y^2/ -3x^2 + 4xy - 3y^2.......if this is the answer...can it be simplified and if so how
Answer That answer is almost right except that it left out y' (dy/dx).
The derivatives of each of the terms is
6x², -6xy-3x²y', 2y²+4xyy', -3y²y', and 0.
We then have 6x² - 6xy - 3x²y' + 2y²+4xyy' - 3y²y' = 0.
Move the expressions without y' to the other side of the equation.
Factor out y' and divide both sides of the equation by the coefficient in front of y'.
