More Calculus Answers
Question Library
Ask a question about Calculus
Volunteer
Experts of the Month
Expert Login
Awards
About Us
Tell friends
Link to Us
Disclaimer
|
| |
|
|
| |
| | | |
About Scotto
Expertise
Any kind of mathematics (algebra, geometry, trigonometry, matrices, calculus, linear approximation, linear regression, linear programming, numerical analysis, probability, statistics, etc.). I also have answered some questions in Physics, Chemistry, and Biology. I would like to volunteer in all areas of Mathematics, not just calculus, and the other three courses that were mentioned.
Experience
Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
| | |
| |
You are here: Experts > Teens > Homework/Study Tips > Calculus > calculus
Expert: Scotto
Date: 7/8/2008
Subject: calculus
Question
i trying to find dx/dy of 2x^3 - 3x^2y + 2xy^2 - y^3 = 2
i came up with dx/dy = -6x^2 + 6xy - 2y^2/ -3x^2 + 4xy - 3y^2.......if this is the answer...can it be simplified and if so how
Answer
That answer is almost right except that it left out y' (dy/dx).
The derivatives of each of the terms is
6x², -6xy-3x²y', 2y²+4xyy', -3y²y', and 0.
We then have 6x² - 6xy - 3x²y' + 2y²+4xyy' - 3y²y' = 0.
Move the expressions without y' to the other side of the equation.
Factor out y' and divide both sides of the equation by the coefficient in front of y'.
Add to this Answer
Ask a Question
|
|
