Calculus/calculus

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Expert: Scotto - 7/8/2008


Question
i trying to find dx/dy of 2x^3 - 3x^2y + 2xy^2 - y^3 = 2
i came up with dx/dy = -6x^2 + 6xy - 2y^2/ -3x^2 + 4xy - 3y^2.......if this is the answer...can it be simplified and if so how

Answer
That answer is almost right except that it left out y' (dy/dx).

The derivatives of each of the terms is
6x², -6xy-3x²y', 2y²+4xyy', -3y²y', and 0.

We then have 6x² - 6xy - 3x²y' + 2y²+4xyy' - 3y²y' = 0.

Move the expressions without y' to the other side of the equation.

Factor out y' and divide both sides of the equation by the coefficient in front of y'.

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Scotto

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

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Maybe not a publication, but I have respond to well oveer 7,500 questions on the PC. Well over 2,000 of them have been in calculus.

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I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

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I have been nominated as the expert of the month several times. All of my scores right now are at least a 9.8 average (out of 10).

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My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.

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