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Expert: Scotto - 7/3/2008


Question
QUESTION: prove that:
sin^2(x) + cos^2(x) = 100

ANSWER: Take a triangle with b as the near side, a as the far side, and c as the hypoteneuse.  It is known that aē + bē = cē for all right triangles.  If we take these measurements and divide by c, instead of a, b, and c we get a/c, b/c, and 1.  Note that a/c is the sin(x) and b/c is the cos(x).  What we then get is sinē(x) + cosē(x) = 1.

I don't know where the 100 came from unless it is suppose to be 1.00.

---------- FOLLOW-UP ----------

QUESTION: Please understand my Question
At what value for (X) does it satisfies
Sin^2(x)+cos^2(x)=100

Answer
The 100 is actually in the question that was asked by you.

This is what was in the question: 'Sin^2(x)+cos^2(x)=100'  Written like this, there are no solutions since the largest sinē(x) and cosē(x) can be is really 1 for any x.

Assuming you really meant 1 so that the equation is sinē(x)+cosē(x)=1.
Again, this is true for all x.  That is one of the trig identities is that sinē(x)+cosē(x)=1 for all x.

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Scotto

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

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Maybe not a publication, but I have respond to well oveer 7,500 questions on the PC. Well over 2,000 of them have been in calculus.

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I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

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I have been nominated as the expert of the month several times. All of my scores right now are at least a 9.8 average (out of 10).

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My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.

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