AboutScotto Expertise Any kind of mathematics (algebra, geometry, trigonometry, matrices, calculus, linear approximation, linear regression, linear programming, numerical analysis, probability, statistics, etc.). I also have answered some questions in Physics, Chemistry, and Biology. I would like to volunteer in all areas of Mathematics, not just calculus, and the other three courses that were mentioned.
Experience Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
ANSWER: Take a triangle with b as the near side, a as the far side, and c as the hypoteneuse. It is known that aē + bē = cē for all right triangles. If we take these measurements and divide by c, instead of a, b, and c we get a/c, b/c, and 1. Note that a/c is the sin(x) and b/c is the cos(x). What we then get is sinē(x) + cosē(x) = 1.
I don't know where the 100 came from unless it is suppose to be 1.00.
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QUESTION: Please understand my Question
At what value for (X) does it satisfies
Sin^2(x)+cos^2(x)=100
Answer The 100 is actually in the question that was asked by you.
This is what was in the question: 'Sin^2(x)+cos^2(x)=100' Written like this, there are no solutions since the largest sinē(x) and cosē(x) can be is really 1 for any x.
Assuming you really meant 1 so that the equation is sinē(x)+cosē(x)=1.
Again, this is true for all x. That is one of the trig identities is that sinē(x)+cosē(x)=1 for all x.