AboutAlon Mandes Expertise Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems.
Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
Experience 1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
Question We have been teached to find the asymptotes of polar curve by using formula-
Rsin(Theta -alpha )=1/f'(alpha )
Where alpha denotes the roots of f (theta)=0
How can we find the asymptote of the polar curve
2r^2=tan2(theta) by using this formula.If there is any links for solving this pls post it as well.
Answer The formula of the asymptotic line is :
g'(Ø)
r = ----------
sin(Ø - Øo)
Where g(Ø)=1/f(Ø) & Øo is the root or solution of g(Ø)=0 or
1/sqrt[0.5tan(2Ø)]=0. Let's solve it :
1/sqrt[0.5tan(2Ø)]=0 means sqrt[0.5tan(2Ø)]=∞ (infinity)
The same as 0.5tan(2Ø)=∞, which also the same as tan(2Ø)=∞.
Now, when does the function tan(2Ø) goes to infinity ? the answer
is when 2Ø=π/2, meaning Ø=π/4, & this is the solution Øo.
Now let's calculate g'(Ø) : g'(Ø)= [1/sqrt[0.5tan(2Ø)]]'=
