AboutScotto Expertise Any kind of mathematics (calculus, analysis, game theory, linear approximation, finite differences, linear regression, linear programming, numerical analysis, probability, statistics, etc.).
I also have answered some questions in
Physics (mass, momentum, falling bodies),
Chemistry (charge, reactions, symbols, molecules), and
Biology.
Experience Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
Publications Maybe not a publication, but I have respond to well oveer 3000 questions on the PC.
That's around 2,000 in basic math and 1,000 in advanced math.
Education/Credentials I aquired well over 40 hours of upper division courses. This was well over the number that were required.
I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few junior level courses my sophomore year.
Awards and Honors I have been nominated as the expert of the month several times.
All of my scores right now are at least a 9.8 average (out of 10).
Past/Present Clients My past clients have been students at OSU, students at the college in South Seattle,
referals from a company, friends and aquantenances, people from my church, and people like you.
Question I was wondering if you could explain what the dx/dy is and how to use it.
And how would you find the derivative of say:
y= (2x-7)^3
And how would you evaluate the derivative fo the function at an indicated point like:
y= 37-sec^3(2x) and the points are (0,36)
The 2x isn't with the cubed...
That would be so helpful! Thankies! :}
Answer The derivative of (f(x))^n is n(f(x))^(n-1)f'(x). Here, f(x)=2x-7 and n is 3.
At (0,36), we have 37-sec^3(0)=36, so all that says is what's true since the sec(0) is 1 and therefore the cube is 1, so 37-1=36 is true as well.
On the function sec^3(2x), 2x is computed, then the secant is taken, and then the value gotten from the secant is cubed. It looked like maybe you were a little unclear when you said the 2x wasn't cubed.
