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Question
(t-4)^2 = (t+4)^2 + 32.
solve the equation
Ok Ashlee, for this kind of equation, we will use a very nice trick.
a trick which is a rule claiming that a^2-b^2=(a-b)(a+b).
In our case, a=t-4, & b=t+4, so our equation now becomes :
a^2=b^2+32 --> a^2-b^2=32, let's apply the rule we get :
(a-b)(a+b)=32. Let's substitute a & b :
[t-4-(t+4)]*[t-4+(t+4)]=32
[t-4-t-4]*[t-4+t+4]=32
[-8]*[2t]=32
-16t=32--> t=-2.
Alon.
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Answers by Expert:
Alon Mandes
Expertise
Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
Experience
1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.
Education/Credentials
M.A in Mathematics & Bs.c in Electronics.
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