About NUR ARINA BASILAH BINTI KAMISAN Expertise i can answer derivatives and integral questions but not so expert in answering limits,vector and infinite series.
Experience i teached calculus for foundation students at university malaya and i also teached tutorial class in university for subject differential equation when i was doing my degree.currently i'm teaching algebra for foundation students.
Education/Credentials i have degree in mathematics with education and now i'm futhering my study in master of statistics at university malaya.
Expert: NUR ARINA BASILAH BINTI KAMISAN - 8/23/2008
Question QUESTION: pleez help me to integrate sin x/cos squared x+cos x-2
ANSWER: hi taahira,
i'm a little bit confuse with your question with cos x-2.is it cos(x-2) or cos(x)-2.i assume it was cos(x)-2.
so when you have to integrate sin x/cos^2(x)+cos x-2,first step is:
let u=cos x then du=-sin xdx
now substitute it into the original equation and you will have:
-du/(u^2+u-2) or
-[1/u^2+1/u-1/2]du
and integrate this you will have:
-[-1/u+ln(u)-u/2]+c
1/u-ln(u)+u/2+c
substitute back u=cos x
1/cos x-ln(cos x)+cos x/2+c
QUESTION: TNX FOR DA RESPONSE..SORI FOR THE AMBIGUITY..JUST ONE MORE Q...WHEN DO YOU USE LN X + C AND WHEN DO YOU USE 1/X +C...WHEN YOYU INTERGRATE THAT IS
Answer dear taahira,
the rule of integration for simple equation is when you have x^a, the integration will become (x^a+1)/a+1 + c
so if you have 1/(x^2),it was also equal to x^-2.integrate this equation,you will have [x^(-2+1)]/(-2+1) + c =x^-1/-1 + c=-1/x + c
and if you have 1/x=x^-1,if you integrate it by using the formula above you will have, x^(-1+1)=x^0.this is incorrect.so for 1/x,the integration will become ln(x) + c.
