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Calculus/Vertical and Horizontal asymptotes

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Expert: Alon Mandes - 9/11/2008


Question
Given the function y = (x-b)/ (2x^2 - 2b^2), find all vertical and horizontal asymptotes. if there are none, state why.

Answer
Kristin notice that (x-b)/(2x^2 - 2b^2)=(x-b)/2(x^2-b^2)=
=(x-b)/2(x-b)(x+b)=1/2(x+b). & this function has 1 horizontal
asymptote at y=0, & 1 vertical asymptote at x=-b.
Let's prove that :

The function 1/2(x+b) decline to zero ax x grows to infinity .
The function 1/2(x+b) jumps to infinity when x=-b because
y(-b)=1/2(-b+b)=1/0=infinity.

Alon.

Calculus

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Alon Mandes

Expertise

Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

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