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Calculus/limit with square roots
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Question
I need to know how to solve the following limit:
lim as x->0 square root (2-t) + square root of (2) / t.
I know the answer is -square root of (2)/4. I just can't figure out how you get there.
Let's define SR(a) as square root (a).
So if you meant :
Lim{t->0} [ SR(2-t)+SR(2) ]/t Then the answer is ∞
& if you meant
Lim{t->0} SR(2-t)+SR(2)/t, the answer is still ∞
As well as Lim{t->0} SR(2-t)+SR(2/t), we still get ∞
Sorry , no room for -SR(2)/4. Chick it again.
I'll be more than happy to explain it to you.
Alon.
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| Comment | Infinity was the answer I kept getting, but the book said the other was the answer. Thank you for your help! | ||
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Answers by Expert:
Alon Mandes
Expertise
Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
Experience
1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.
Education/Credentials
M.A in Mathematics & Bs.c in Electronics.
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