Expert: Ahmed Salami - 1/27/2009

Question
Thanks for helping me with this. the problem is= p^5ln(p)dp
u = Ln p  dv= p^5 dp
du= (1/p)dp  v= (1/6)p^6
i'm stock on the second part where I get - the part to
integrate= to (1/6)S p^6(1/6) dp im tire and I cant seem to
get the right answer or be able to solve this .

Answer
Hi Israel,
You've really done well.
The last part is to integrate v.du i.e
&(1/6)p^6.(1/p)dp  where & represents the integral sign.
&(1/6)p^6.(1/p)dp  = &(1/6)p^5 dp
= (1/6)(1/6)p^6
= (1/36)p^6
From what i can see, your mistake was when you wrote [(1/6)&p^6(1/6) dp] instead of [(1/6)&p^6(1/p) dp], mistakenly putting 1/6 instead of 1/p.

Regards