Calculus/Hw. Help.

Advertisement


Question
Assume the following and evaluate the given expression

sin(x)= 12/13, 0 < x < x/2

find.
sin(4x)=


I thought you could use the formula of sin (2x) and replace it with a 4, but I don't think that's right because i don't come out with the right answer.

Answer
sin(2x)=2sin(x)cos(x)
Here we have sin(x) = 12/13, so the cos(x) = 5/13.

{ you know, if one leg is 12 and the hypoteneuse is 13, the other leg is 5, which I just mentioned in the last problem }

This would mean that the sin(2x) = 2(12/13)(5/13) = 120/169.

With angle 2x, the far side is 120, the hypoteneuse is 169,
and the near side is root(169^2 - 120^2) = root(28,561 - 14,400)
= root(14,161). Using this, the cos() of that angle can be found.

The sin(4x)=2sin(2x)cos(2x), both of which were just found.

Multiply them together while taking a squareroot and you've got the answer.  

Calculus

All Answers


Answers by Expert:


Ask Experts

Volunteer


Scotto

Expertise

Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

Experience

Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

Publications
Maybe not a publication, but I have respond to well oveer 7,500 questions on the PC. Well over 2,000 of them have been in calculus.

Education/Credentials
I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

Awards and Honors
I have been nominated as the expert of the month several times. All of my scores right now are at least a 9.8 average (out of 10).

Past/Present Clients
My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.

©2012 About.com, a part of The New York Times Company. All rights reserved.