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Calculus/u-substitution in trigonmetric equations involving sin, cos, and tan

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Question
Hi.  I have been struggling a bit in my trig class trying to understand u-substitution.  An example of the type of equation that trips me up is:

4sin^2(theta)=1

I can get as far as theta=pi/6 but I don't know where to go from there. my teacher wants us to find the location(s) on the unit circle and she said something about adding 2*pi*K to the answer.  Can you please explain to me what I am supposed to do and if I am even doing it right?  Thanks!

Answer
We know that sin(Θ) = 1/2, so you're right in saying that Θ=π/6.
If you know what the sin(x) curve looks like, it start at 0,
goes up to 1 at π/2 radians, back to 0 at π radians,
down to -1 at 3π/2 radians, and back to 0 at 2π radians.

On the interval (0,π), it is symmetric about π/2.
Our answer, π/6 radians, is π/3 radians below π/2.
Another answer would be π/3 radians above π/2,
which would be 5π/6 radians.

Overall, the solution would be π/6 + 2kπ or 5π/6 + 2kπ radians with k as an integer.

This is because if you add 2π radians to an angle, it comes back around to the same angle since there are 2π radians in a circle.

I'm not sure you really need to find the other angle
(in this case, 5π/6), but adding on 2kπ for some integer k brings the answer around the circle back to the same angle.

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