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Calculus/quotient rule

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Question
find f'(x)of (10xx+2) and the whole thing square root

Answer
If that f(x) = √(10x² + 2) ?

Note that √ is the same as ^(1/2) { to the 1/2 power }.

To take the derivative, reduce the power by 1, so it becomes at -1/2.  This is 1/√.

Then f'(x) = [(1/2)/√(10x² + 2)](20x) = 10x/√(10x² + 2).

The 10x² is inside the squareroot, and the derivative of that is 20x.  When this is multiplied by ½, 10x is gotten.

Notes:
√ is alt-251 and ² is alt-253.
I put them into a special spreadsheet in my \computer directory on my PC
along with several other special characters like greek letters, ½, and ³.

Occasionally those characters don't work, so sqrt(x) is the squareroot of x.
Shift 6 (^) is used for x to a power.  x^3 is x cubed, x^5 is x to the fifth.

Calculus

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