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Question
Find critical numbers and relative maximum(s), and relative minimum(s) of f(x)=x^4-6x^2+2
f(x)=x^4-6x^2+2
f'(x)=4x^3-12x
f'(x)=0 : 4x^3-12x=0 --> x(4x^2-12)=0 . Solutions : x1=0, x2=√3, x3=-√3 . These are the
critical points .
f''(x)=12x^2-12 .
f''(0)=-12 --> -12<0 then x1=0 is a max point .
f''(√3)=-12 --> 96>0 then x2=√3 is a min point .
f''(-√3)=-12 --> 96>0 then x2=-√3 is a min point .
Alon.
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Alon Mandes
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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
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1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
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M.A in Mathematics & Bs.c in Electronics.
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