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Calculus/Velocity, acceleration and curvature
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Question
Hi please see attached image for the question.
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I know that for the first question i need to find the derivative and then the double derivative, but i cam continually getting the wrong answer
R(t)=2t[i] + 3t^2[j] + sin(t)e^(-t)[k]
Velocity=V(t)=dR/dt=R'(t)=2[i]+6t[j]+ { cos(t)e^(-t)-sin(t)e^(-t) }[k]
I followed the rule : [fg]'=f'g+fg'
Acceleration=A(t)=R''(t)=V'(t)=
=0[i]+6[j]+ { -sin(t)e^(-t)-cos(t)e^(-t)-cos(t)e^(-t)+sin(t)e^(-t) }[k]
Alon.
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Answers by Expert:
Alon Mandes
Expertise
Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
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1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
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Education/Credentials
M.A in Mathematics & Bs.c in Electronics.
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