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Question
Find the intervals of increase or decrease, local max and min, concavity and points of inflection.
y= x/x^2-9

Answer
y=x/(x^2-9)
y'=[x^2-9-x(2x)]/(x^2-9)^2
y'=0 : x^2-9-2x^2=0 --> x^2+9=0 . No solution in the real numbers of x .
Therefore, there are to critical points. There is however a vertical asymptote at x=3 and -3 .
y is increasing for all -3<x<3
y is decreasing for all x<-3 and x>3

Alon.

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

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M.A in Mathematics & Bs.c in Electronics.

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