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Calculus/Calculus Help! Abs Max and Abs Min

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Expert: Alon Mandes - 12/6/2009


Question
Find the absolute maximum and absolute minimum for the function on the indicated interval.              f(x)= x^2-8x+21 on [0,6]            - Can you show the work so I understand how to do it? Thanks!-

Answer
1st step , let's chick the edges :
f(0)=21.
f(6)=9 .
Now, let's derive & solve f'=0 :
f'(x)=2x-8
f'=0 : 2x-8=0 --> x=4 .
Now, let's chick if x=4 is max or min :
f''(x)=2 , therefore f''(4)=2 > 0 So, it's minimum .
f(4)=5 .

Absolute Max : f(0)=21 at x=0
Absolute Min : f(4)=5  at x=4

Alon.

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

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M.A in Mathematics & Bs.c in Electronics.

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