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Question
ok ...i seem to be having a problem sending you the questions so may be i can word it correctly. one question i have
i have find the integral of cosx/(1-cos^2x)
f(x)=cos[x]/(1-cos[x]^2)=cos[x]/sin[x]^2 . ("cosx[x]^2+sin[x]^2=1") .
Note that (sin[x])'=cos[x] & [1/f(x)]'=-f'(x)/f(x)^2 . So we can conclude that
cos[x]/sin[x]^2=(1/sin[x])' . Thus :
Integral of { cosx/(1-cos^2x) } = Integral of { (1/sin[x])' } = -1/sin[x] .
Alon.
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Answers by Expert:
Alon Mandes
Expertise
Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
Experience
1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
students who have problems in mathematics.
3. 2 years of experience as a math teacher in college.
4. I give free homework help for high school students in
Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.
Education/Credentials
M.A in Mathematics & Bs.c in Electronics.
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