Calculus/Applications of Derivatives
Expert: Paul Klarreich - 2/21/2009
QuestionThe spread of a virus is modeled by N=-t^3+12t^2, 0<=t<=12, where N is the number of people infected(hundreds) and t is the time (weeks).
"When will the virus be spreading most rapidly?" I am not sure what the question is asking for. Is it the maximum rate of change? Please respond ASAP. Thank you.
AnswerQuestioner: Romel
Category: Calculus
Private: No
Subject: Applications of Derivatives
Question: The spread of a virus is modeled by N=-t^3+12t^2, 0<=t<=12, where N is the number of people infected(hundreds) and t is the time (weeks).
"When will the virus be spreading most rapidly?" I am not sure what the question is asking for. Is it the maximum rate of change? Please respond ASAP. Thank you.
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Yes, I think the maximum rate of change is the proper interpretation. So you want the largest value of N'(t), for which you will look for inflection points:
N' = 3t^2 + 12t,
N'' = 6t + 12.
Now if you set that = 0, you get t = -2. But that is not in your specified interval, [0,12].
Therefore, the maximum will have to be at one of the endpoints.
Try N'(0) and N'(12). Whichever OF THOSE gives you the max is your answer.