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Calculus/Calculus Integration
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Question
Ok hello again. My question is I have to integrate & e^(-
3x) when x goes from 1 to infinity .
So I tried to do the problem integration e first and then
taking the limit as t goes to infinity and my answer was
that it converges and the pt was (-e^-3)/3 is this correct?
it does not seem right to me.
To integrate e^(-3x), all you've got to do is to divide by the multiplier. The answer is e^(-3x)/(-3). Now if you evaluate this
from 1 to ∞, you get e^(-3*∞)/(-3) - e^(-3)/(-3). The first term is 0 and there are two negatives in the second term. Even though it
may not seem right to you, it is.
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