Calculus/Continuity
Expert: Paul Klarreich - 2/12/2009
Question
A swimmer crosses a river starting at point A and ending at point B, following the path shown below. Prove
that for some value x, the swimmer's distance d (Px, A) from A is the same as the distance d (Px, B) from
B.
AnswerQuestioner: Mona
Private: no
A swimmer crosses a river starting at point A and ending at point B, following the path shown below. Prove that for some value x, the swimmer's distance d (Px, A) from A is the same as the distance d (Px, B) from B.
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This is a matter of giving names to your variables -- the things that change. (you will want to do this when you get to Related Rates and Max-min problems, so you might as well start now.)
Let s = the arc length along the path from A to B. (actual swimming distance)
x = the horizontal distance from a, and a function of s
PA = the actual distance of the swimmer from A. also a function of s.
PB = the actual distance of the swimmer from B. also a function of s.
D = AB, the distance from A to B (a constant)
Observe that as the swimmer swims, s always increases.
Also, x always increases.
Also, the swimmer never 'jumps', so x(s) is continuous.
So is PA(s), and so is PB(s)
PA(s) starts at 0, and finishes with a value of D.
PB(s) starts at D, and finishes with a value pf 0.
Let Diff(s) = PA(s) - PB(s).
Diff(s) starts at 0 - D = -D.
Diff(s) finishes at D - 0 = +D.
So Diff(s) is a continuous function of s with values that include +D and -D.
You take it from there.