Calculus/calculus

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Expert: - 2/26/2009


Question
prove that,if the sum of the radii of two circles remains constant,the sum of the areas of the circles is least when the circles are equal

Answer
R is the total of circles with radius S and T.  Note that T = R-S.
The total area is π(Sē + Tē).

Replace T with R-S and note that R is a constant.

Take the derivatie and set is equal to 0.

The solution should be when S=R/2, so T=R/2 as well since S+T=R.

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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