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Calculus/Calc 2 evaluating improper integrals

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Question
evaluate the improper integrals or show that it diverges.
1. integral from 0 to 9 of ((e to the sq. root x) divided by sq. root x).

2.  integral from 1 to infinity of (x+1)/x squared

Answer
Let's start with section 2:

∫ (x+1)/x  dx
1
We will use the rule :
If f(x)>g(x) in open interval [1,∞) &

∫ f(x) dx Diverge, Then
1

∫ g(x) dx Diverge as as well.
1

We know that (x+1)/x = 1+1/x , & we know also that 1+1/x > 1/x.

∫ 1/x  dx = Lim Ln(t) = ∞
1            t->∞
Thus :

∫ (x+1)/x  dx -> ∞
1

---------

As for section 1:

9
∫ [e^(√x)]/(√x)
0
We will evaluate the integral using Trapezoid Rule :
∆x=(9-0)/n where n=4.
9
∫ f(x) dx = [∆x/2]*[f(xo)+2f(x1)+2f(x2)+..+2f(xn-1)+f(xn)]
0
Thus :
x0=9/4   x1=18/4    x2=27/4   x3=9
9
∫ [e^(√x)]/(√x) = [9/8]*[e^(√(9/4)/√(9/4) + e^(√(18/4)/√(18/4) +
0
e^(√(27/4)/√(27/4) + e^(√9)/√9 .

I'll leave it for you to complete the calculations.

Alon.

Calculus

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

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