Calculus/Graph sketching
Expert: Paul Klarreich - 3/23/2009
QuestionWill you please help me figure out these things I cant figure them out. Thank you so much.
given the equation f(x)= 9*Sqrt(x)*e^(-x)
a) Find the interval on which f is increasing.
b) Find the interval on which f is decreasing.
c) Find the local maximum value of f.
D) Find the inflection point.
e) Find the interval on which f is concave up.
f) Find the interval on which f is concave down.
AnswerQuestioner: cornelius
Country: United States
Category: Calculus
Private: No
Subject: Calculus how derivatives affect the shape of a graph
Question: Will you please help me figure out these things I cant figure them out. Thank you so much.
given the equation f(x)= 9*Sqrt(x)*e^(-x)
>> It is not clear WHY you can't figure them out, so I will get you started. If you get stuck, tell me what you did and I'll see If I can help.
If
f(x) = Sqrt(x) e^(-x) << the 9 is a waste of time.
Find f'(x) using the product rule:
e^(-x)
f'(x) = --------- - sqrt(x) e^(-x)
2 sqrt(x)
Do a little algebra:
1 - 2x
f'(x) = e^(-x) -------
sqrt(x)
Now keep in mind that:
1. e^(anything) is positive,
2. sqrt(x) is positive
and you will have little trouble with these:
a) Find the interval on which f is increasing.
>> find where f' is positive. That basically means 1-2x > 0
.......................
b) Find the interval on which f is decreasing.
>> find where f' is negative. That basically means 1-2x < 0
.........................
c) Find the local maximum value of f.
>> find where f' is zero. That basically means 1-2x = 0
..........................
D) Find the inflection point.
You will have to find f''(x). [Sorry,but that will be some work for you, with both quotient and product rules.]
Then set that f''(x) = 0.
e) Find the interval on which f is concave up.
>> find where f'' is positive.
.....................................
f) Find the interval on which f is concave down.
>> find where f'' is negative.
..........................................