Calculus/calculus

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Expert: Alon Mandes - 3/31/2009


Question
determine the volume of the solid of revolution obtained when the curve: f(x)=x^2+2 is rotated one resolution about the axis,between the limits x=-2 and x=2

Answer
Volume of revolution is : V=π∫f²(x)dx. In our case :
   2
V=π∫(x²+2)²dx =
 -2

   2
V=π∫(x^4+4x²+4)dx =
 -2

                       2
V=π[(1/5)x^5+(4/3)x³+4x|  
                      -2

I'll leave it for you as an exercise to continue.

Alon.  

Calculus

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Alon Mandes

Expertise

Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

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