Calculus/Calculus

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Expert: Alon Mandes - 4/29/2009


Question
By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made. If the cardboard is 16 in. long and 6 in. wide, find the dimensions of the box that will yield the maximum volume.

Answer
If the corners were cut x inches deep, then the volume of the
box will be : V=6x(16-2x). To max we derive & set the derivative equals zero :
V'(x)=6(16-2x)-12x
V'(x)=0 -> 12x=96-12x² -> 12x²+12x-96=0 -> x²+x-8=0 . The solution
is x=2.37
Thus, The dimensions of the maximum volume box are :
Length = 11.25
Width = 6
Height = 2.37

Alon.

Calculus

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Alon Mandes

Expertise

Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

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