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Calculus/Mean of means

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Hi Paul,

I have a problem with a maths homework question.

If you know the average duration (in days) a large group of patients was on a drug, and you also know the average cumulative (total) dose this group of patients received while on the drug - from these two data do you know the average mean daily dose they received?  ie. can you do;

'average cumulative dose/average duration in days on drug = average mean daily dose'

Or, alternatively, to know the average mean daily dose the group of patients received while on the drug would you have to work out each individual's daily dose of the drug from their individual duration on the drug and their individual cumulative dose data and then work out the mean of this?

Because I can't help thinking that if you just divided the mean cumulative dose by the mean duration on the drug that - if, for example, the few patients with much higher cumulative doses were the same few patients who were on the drug for a much shorter duration, then your average mean daily dose figure would turn out higher than it should.

Which method should I use to work out the average mean daily dose the patients received?

Thanks for your time.

From Marc

Answer
Questioner:   Marc
Country:  United Kingdom
Category:  Calculus
Private:  No
 
Subject:  averages problem
Question:  Hi Paul,

I have a problem with a maths homework question.

If you know the average duration (in days) a large group of patients was on a drug, and you also know the average cumulative (total) dose this group of patients received while on the drug - from these two data do you know the average mean daily dose they received?  ie. can you do;

'average cumulative dose/average duration in days on drug = average mean daily dose'

Or, alternatively, to know the average mean daily dose the group of patients received while on the drug would you have to work out each individual's daily dose of the drug from their individual duration on the drug and their individual cumulative dose data and then work out the mean of this?

Because I can't help thinking that if you just divided the mean cumulative dose by the mean duration on the drug that - if, for example, the few patients with much higher cumulative doses were the same few patients who were on the drug for a much shorter duration, then your average mean daily dose figure would turn out higher than it should.

Which method should I use to work out the average mean daily dose the patients received?

Thanks for your time.

From Marc
..............................
Hi, Marc,  

I don't think they are the same.

Patient A:  Takes 10 g  over 2 days.  = 5 g/day

Patient B:  Takes 10 g  over 5 days.  = 2 g/day

Average those:  3.5 g/day/patient.

Now do it by totaling:

Average dose:  10 g.
Average duration:  3.5 days.

10/3.5 = 2.83 (approx) , not  3.5

Does that help?

Calculus

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Paul Klarreich

Expertise

All topics in first-year calculus including infinite series, max-min and related rate problems. Also trigonometry and complex numbers, theory of equations, exponential and logarithmic functions. I can also try (but not guarantee) to answer questions on Analysis -- sequences, limits, continuity.

Experience

I taught all mathematics subjects from elementary algebra to differential equations at a two-year college in New York City for 25 years.

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(See above.)

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