Calculus/Trigonometric limit
Expert: Paul Klarreich - 4/30/2009
QuestionHi, So I have a worksheet that is just to help us get started before we start our next lesson and I was just really confused on it because I can't get one part of the sheet without getting something else. So anything helps!
1. Find lim cos(theta)-1
(theta)->0 ------------
(theta)
using the following outline:
a) multiply by cos(theta)+1
------------
cos(theta)+1
b) Use the Pythagorean identity to simplify the numerator
c) rewrite the fraction as a product of two fractions, where one of the fractions is sin(theta)
----------
(theta)
d) use limits laws to find lim cos(theta)-1
(theta)->0 ------------
(theta)
AnswerQuestioner: ray
Country: United States
Category: Calculus
Private: No
Subject: just some randoms
Question: Hi, So I have a worksheet that is just to help us get started before we start our next lesson and I was just really confused on it because I can't get one part of the sheet without getting something else. So anything helps!
1. Find lim cos(theta)-1
(theta)->0 ------------
(theta)
using the following outline:
a) multiply by cos(theta)+1
------------
cos(theta)+1
b) Use the Pythagorean identity to simplify the numerator
c) rewrite the fraction as a product of two fractions, where one of the fractions is sin(theta)
----------
(theta)
d) use limits laws to find lim cos(theta)-1
(theta)->0 ------------
(theta)
..........................................
Hi, Ray,
This is a standard derivation found in most calc texts. You are going to use this limit fact:
sin t
lim -------- = 0
t->0 t
{BTW, I will use t for theta to save typing.]
Find
lim cos(t)-1
t->0 ------------
t
using the following outline:
a) multiply by cos(t)+1
------------
cos(t)+1
.........................
lim cos(t)-1 cos(t)+1
t->0 --------- ---------
t cos(t)+1
lim cos^2(t)-1
t->0 --------------
t (cos(t)+1)
lim - sin^2(t)
t->0 --------------
t (cos(t)+1)
lim - sin(t) sin(t)
t->0 --------------
t (cos(t)+1)
lim - sin(t) sin(t)
t->0 ---------- -----------
t (cos(t)+1)
..........................
lim - sin(t) lim sin(t)
t->0 ---------- t->0 -----------
t cos(t) + 1
<<< first part >> << second part >>
OK, the first part --> -1 because of that earlier 'fact'.
The second part --> 0/1 = 0
So the product is zero.