You are here:

Calculus/Please help me out with this quetion

Advertisement

Expert: Alon Mandes - 5/14/2009


Question
integrate this;
1. cos inverse (3x)dx
2.dx/(4-9x^2)^2
3.x^2 dx/(x^2-3x+2)

Answer
1. ∫Arcos[3x] dx
In this section we will use integration by parts :
∫dvu=vu-∫vdu
We will take : dv=1 & u=Arcos[3x] . Thus, our integral will become:
∫Arcos[3x] dx = Arcos[3x] - ∫xdx/√(1-9x²) dx
Note that the derivative of √(1-9x²) is 18x/√(1-9x²) . Hence :
∫Arcos[3x] dx = Arcos[3x] - ⅓√(1-9x²) .
---------------------------------------
As for sections 2 & 3 , I've solved the exact problems. Please
browse throught my Answered questions.

Alon.

Calculus

All Answers

Answers by Expert:

Ask Experts

Volunteer

Alon Mandes

Expertise

Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

Organizations
Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

©2012 About.com, a part of The New York Times Company. All rights reserved.