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Question
given y=sinx(1-cosx) show dy/dx=(1+2cosx)(1-cosx)
Hi Olivia,
y = sinx(1-cosx)
Using the product rule
dy/dx = sinx d/dx(1-cosx) + (1-cosx)d/dx(sinx)
= sinx.sinx + (1-cosx)cosx
= (sinx)^2 + (1-cosx)cosx
= [1 - (cosx)^2] + (1-cosx)cosx
= (1-cosx)(1+cosx) + (1-cosx)cosx
factorizing with (1-cosx), we have
dy/dx = (1-cosx)[(1+cosx) + cosx]
= (1-cosx)(1+2cosx)
Regards
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Calculus
Answers by Expert:
Ahmed Salami
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I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I believe i would be very helpful in calculus and can as well help a good deal in Physics with most emphasis directed towards mechanics.
Experience
An engineering graduate. I have been doing maths and physics all my life.
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