Expert: Ahmed Salami - 5/19/2009

Question
Find the volume of the function formed by revolving the function x=-(y-
2)^2+1 around the x-axis. I hate this section! Please help, thank you

Answer
Hi Ryan,
The volume of the solid formed when y = f(x) is rotated around the x axis is
V = ∫#y^2 dx |a to b (i.e between x = a to x = b, where # represents pi)
You've not specified any limits here. Also note that,
For x = -(y-2)^2 + 1
x can only takes values in the range x ≤ 1

Regards