AboutScotto Expertise Any kind of mathematics (calculus, analysis, game theory, linear approximation, finite differences, linear regression, linear programming, numerical analysis, probability, statistics, etc.).
I also have answered some questions in
Physics (mass, momentum, falling bodies),
Chemistry (charge, reactions, symbols, molecules), and
Biology.
Experience Experience in the area: I have tutored students in all areas of mathematics for over 20 years.
Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors.
Awards and Honors: I have passed Actuarial tests 100, 110, and 135.
Publications Maybe not a publication, but I have respond to well oveer 3000 questions on the PC.
That's around 2,000 in basic math and 1,000 in advanced math.
Education/Credentials I aquired well over 40 hours of upper division courses. This was well over the number that were required.
I graduated with honors in both my BS and MS degree from Oregon State University.
I was allowed to jump into a few junior level courses my sophomore year.
Awards and Honors I have been nominated as the expert of the month several times.
All of my scores right now are at least a 9.8 average (out of 10).
Past/Present Clients My past clients have been students at OSU, students at the college in South Seattle,
referals from a company, friends and aquantenances, people from my church, and people like you.
Since F(x) is used for ∫f(x)dx, it can be seen that there are no limits, which means there must be a '+ C' on the final result.
That limits the choices to (C) or (D).
It is also known that integration increases the power on x,
which mens that we are looking for a power of 2+1 = 3.
Since we are down to (C) and (D), the power in (C) is 3 and the power in (D) is 1. Since we are looking for a 3, is is (C).
The other approach is knowing how to do the problem.
To integrate, add one to the power and divide by the new power.
Since the current power is 2, the new power is 3 and the entire expression is divided by 3. Since there is a 3 in the expression already, it is known that 3/3 is 1, so that disappears and the answer is x^3. '+ C' is added since there are no limits'
