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Question
what is the diffrentiation of f(x)log5^(lnx)+log2^(lnx+2)
Hi,
f(x) = log5^(lnx) + log2^(lnx+2)
= (lnx)(log5) + (lnx+2)(log2)
= (lnx)(log5) + (lnx)(log2) + 2log2
= (lnx)(log5 + log2) + 2log2
= (lnx)log(5.2) + 2log2
= (lnx)log10 + 2log2
= lnx + 2log2
Therefore,
f'(x) = 1/x
Regards
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Calculus
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Ahmed Salami
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I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I believe i would be very helpful in calculus and can as well help a good deal in Physics with most emphasis directed towards mechanics.
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