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Question
What is the integral of log 10x?
Log10(x)=Ln(x)/Ln(10)
Integral of {Log10(x)} = Integral of {Ln(x)/Ln(10)} =
[1/Ln(10)]*Integral of {Ln(x)} . To calculate this integral we
use the method of "Integration By Parts" :
INT{u'v}=uv-INT{uv'} . In our case : u'=1 & v=Ln(x) . Thus,
INT{Ln(x)}=xLn(x)-INT{1}=xLn(x)-x .
Therefore :
Integral of {Log10(x)} = xLog10(x) - x/Ln(10) .
Alon.
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Alon Mandes
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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
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1. I'm a team member of mathnerds (math site for answering questions)
2. I'm a team member in the Student's Union of the Technion, helping
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3. 2 years of experience as a math teacher in college.
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Mathematics & Physics.
5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" ,
"Complex Functions".
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M.A in Mathematics & Bs.c in Electronics.
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