Expert: Scotto - 7/31/2009

Question
QUESTION: I was going to mention an interesting thought about that derived equation

         dV/dt[{V/2A[1-H^3/12c^3]-2/3}+1/2}

To me this looks like a "slice' through a process which I previously described as a "molasses-style "atmosphere. A kind of compression with relaxation seems to be in place and this can be seen as proces in which things seem to slow down during tornado formation, something described by scientists assiciated with studies of right turning storms in whcih once these storms turn right, these slow down akin to a rolling bottle that rotates at constant rate. Anyway, part of the smaller numbers like the value A can be shown to be approximating the value $ times the sqrt of teh area divided by 3, hence, a smaller version of the 4piabH/3 value of cone and cyl;inder system. To me, this is kind of like smaller versions within the scope of the overall, like finding smaller versions of the Mandelbrot Set within itself at more microscopic levels! Chaos? I do not know!

ANSWER: I think one of the equations is (dV/dt)[{V/(2A)}{1 - H^3/(12c^3)} - 2/3] + 1/2.

Again, it is very useful to check the brackets, braces, and parenthesis.

Notice that only the 1 - H^3/(12c^3) is multipliplied by V/(2A).

It looks like the 2/3 is subtracted before multiplying by (dV/dt).

It looks like the 1/2 is suppose to be added on at the end.

Is this correct?


---------- FOLLOW-UP ----------

QUESTION: I believe that you are correct with the statement if the dV/dt is essentially removed, leaving 1/2 to be added! Again, I am more curious about the relationship

         y''+y'+piabH[1+1/3(H^2/c^2)]-4piabH/3=0

which is supposed to be the acceleration plus velocity of a cloudform of this volume such that it eventually reaches the minimum volume 4piabH/3. I have also tried a variation

         y''+y'+piabH[1+1/3(H^2/c^2)]-y'4piabH/3=0

with y'=2A/3V and y''=-2A/3V^2.

Answer
That's y' and y", which are dy/dV and d²y/dV² - right?

By the way, π is alt-227.  I do an alt-227, highlight π, and do a control-c.

Now all that has to be done every time I want π is to hit control-v π
and π shows up again π and again π and again π at just a strok of the fingers each time.

Ooou!  There's pi on my fingers!
I guess that's OK, since π is made of numbers, not blackberry or cherry or apple...