Expert: Scotto - 7/22/2009

Question
QUESTION: It is much more than wind and pressure, it may concern the "heart". If the cardioid is a solution to a balancing term for field pressure and horizontal velocity which is taught in beginning meteorology programs, then the cardioid may be that which is the patterning agent for tornado outbreaks. The specificity in location and timing for  these storms indicates far more than mere randomness can, because of the identification of alternating series/sequencing in the Super outbreak. That regularity throws out pure randomness, I will accept quasi-periodic as a basis for discussion, but not shear randomness. That in itself suggests a need to take a closer look. Incidentally, the argument about using the cloud volume found in the Hyperboloid of One Sheet when subjected to acceleration and velocity concerns as a differential equation has for its solution a type of compression which would be consistent with a "molasses-type atmosphere"!  That is pdp/dy+dp/dy+piabH[12+1/3{H^2/c^2}]-4piabH/3=0 has as a solution  pdpdy[dp/2A[1-H^3/12c^2]-2/3]+1/2]. Do you concur?

ANSWER: Thank you for the response.  
Here is a response with questions about it.


Let me see if I've got it.  Is the equation is
p(dp/dy) + dp/dy + piabH[12 + 1/3(H²/c²)] - 4piabH/3 = 0?
Note that dp/dy is also written as p'(y).

What is piabH?  Is it piab * H?  Is H for heat?  
Or is piabH for something else,
like pi... absorbant Heat?  (Just guessing)?.


The solution as pdpdy[dp/2A[1-H^3/12c^2]-2/3]+1/2]
p(dp/dy)[dp/2A[1-H^3/12c^2] - 2/3] + 1/2],
but I'm a little bit confused.

Is the dp just over 2? 2A? 2A[1-H^3/12c^2]?
There are only 2 '[', but 3 ']'.
Maybe the 2A should be a dA.

Division and multiplication have the same precedence.
This means that 1/2*4 is really read as 1/2 of 4, which is 2.
Yet sometimes it might suppose to be 1/(2*4), which is 1/8.

In my head there might be a Super Outbreak as I grasp to understand what we are talking about.  It looks like just a combination of differential equations and the weather.  Now that seems to make a tornado in my mind...


---------- FOLLOW-UP ----------

QUESTION: piabH is intended to be a right cylinder of height,H. Hence, piabH could as well be written pir^2H but a and b could as well be different radii. My point was to take a cloud with a volume that has been described as a hyperboloid of one sheet subject it to change in acceleration and velocity in order to obtain 4piabH/3, or, a right cylinder with cone system, otherwise known as tornado with updraft. When I incorporate as velocity the term, 2A/3v, I get what I submitted but I neglected to inform you of this. You see, 2A/3v is an interesting upper limit I found in many outbreaks. It appears to be akin to the Navier-Stokes relationship dealing with drag coefficients. In other words, a cloud given the requirements that I have noted is "transformed" into a minimum due a lot to apparently to atmospheric drag. Also note that vorticity was never employed but might as well be an outcome, hence, it is effect rather than cause, indicating that absolute vorticity, itself, a contrivance, may never be involved! I originally got a solution employing the system Professor Fujita apparently derived employing a system of both updraft and downdraft, which he called "tornado cyclone" conditions! I need to contine this discussion where ever it takes I have been working on this for so long!

ANSWER: I find it rather fascinating the they have the mathematics that determine a tornadoes behavior.

So is p(dp/dy) + dp/dy + piabH[12 + 1/3(H²/c²)] - 4piabH/3 = 0
the right equation?

It would also be great if you clarified
pdpdy[dp/2A[1-H^3/12c^2]-2/3]+1/2],
since there are 3 ']' but only 2 ']'.

Also, where it says pdpdy it really means p(dp/dy).  Right?



---------- FOLLOW-UP ----------

QUESTION: The equation  is:

pdp/dy+dp/dy+piabH[1+1/3(H^2/c^2)]-4piabH/3=0  where 2A/3v should substitute for dp/dy as well as the appropriate acceleration term, I believe to be -2A/3v^2. Incidentally, do you like series/sequence problems for if you do, tornado outbreaks are apparently built on series/sequence problems as I can show later!

Answer
Just thought I might tell you that pi is really π (alt-227).

I have a trivial question for you: why do you use A and v?
shouldn't they be A and V? You could use 'a', but that would almost look like part of a sentence.

If we read, 'Would you like any a with that?'
we'd think a ... ? like, what goes in there.
However, if we read, 'Would you like any A with that?'
we'd think, 'Yes, A would be good.'

Of course, if you remember, 'Happy Days' on TV, it was always
"Aaaaaa" by Fonzie, complete with both arms outstretched and both thumbs up.

Now there's another angle on things ...

See, Fonzie probably liked pie,
but I don't think he ever think of π ...