Calculus/physics

Advertisement


Question
QUESTION: i have an expression which has a scalar quantity in left hand side is equal to dot product of two vectors whole square[ex. g=constant*(a.b)^2], where a and b are vectors and g is a scalar. How to remove the square of the dot product?



ANSWER: Since the square looks like it is outside the dot product,
it can be said if your equation is g = k(a∙b)²,
then what can be said it that √(g/k) = a∙b.


---------- FOLLOW-UP ----------

QUESTION: thank you sir for your suggestion. now the next question that follow up the previous one is how to convert the same equation as a sum of two vectors?
example: sqrt(g/k)= a+b, where a and b are vectors.

Answer
The dot product of two vectors is an integer.
However, the sum of two vectors is still a vector.
It makes no sense to say that a numer is a vector.

If you squared both sides, you would have g/k = (a+b)²,
but since a and b are vectors, (a+b)² is a matrix.

You could then say that g = k(a+b)²,
but that is a single value is equal to a matrix.
Maybe g is the |k(a+b)²|.

Calculus

All Answers


Answers by Expert:


Ask Experts

Volunteer


Scotto

Expertise

Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

Experience

Experience in the area: I have tutored students in all areas of mathematics for over 25 years. Education/Credentials: BSand MS in Mathematics from Oregon State University, where I completed sophomore course in Physics and Chemistry. I received both degrees with high honors. Awards and Honors: I have passed Actuarial tests 100, 110, and 135.

Publications
Maybe not a publication, but I have respond to well oveer 7,500 questions on the PC. Well over 2,000 of them have been in calculus.

Education/Credentials
I aquired well over 40 hours of upper division courses. This was well over the number that were required. I graduated with honors in both my BS and MS degree from Oregon State University. I was allowed to jump into a few junior level courses my sophomore year.

Awards and Honors
I have been nominated as the expert of the month several times. All of my scores right now are at least a 9.8 average (out of 10).

Past/Present Clients
My past clients have been students at OSU, students at the college in South Seattle, referals from a company, friends and aquantenances, people from my church, and people like you from all over the world.

©2012 About.com, a part of The New York Times Company. All rights reserved.