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Calculus/Limits of infinity

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Question
I need help on finding the limit as x goes to infinity of (5/x^3-cos1/x)(3+cos1/x)

Answer
The Limit is -4 . Her's why :
Lim    (5/x^3-cos1/x)(3+cos1/x) = (5/INF-cos1/INF)(3+cos1/INF) = (0-cos(0))(3+cos(0)) =
x->INF

= -1*(3+1) = -4 .

Of course this is an immediate & quick technique . It can be also proved elegantly by the definition of limits.

Alon.

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

Experience

1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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Hi-Tech company : GSM4VOIP ; job possition : Algorythm developer.

Education/Credentials
M.A in Mathematics & Bs.c in Electronics.

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