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Calculus/derivative of equation

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Expert: Alon Mandes - 9/9/2009


Question
derivative: sqrt(log3^(x^2-x))

i simplified to sqrt( (x^2-x) * (log3) )

then i used the product rule and chain rule

(2x-1)*(log3)^(.5) / (2(x^2-x)^(.5)) + (x^2-x)^(.5) / (2log3)^(.5)


I hope that you can see what my answer is. Anyway, i don't think this is the right answer and would appreciate any help with this problem.

Answer
In this case there is no need for the product rule, note that log(3) is a constant .
Sqrt[ (x^2-x) * (log3) ] = Sqrt[ (x^2-x) ] * Sqrt[ (log3) ] = Sqrt[ (x^2-x) ] * 0.69   .
Now let's derive the sqrt function:
Sqrt[x^2-x]' = (2x-1) / 2*Sqrt[x^2-x] . Therefore :
Sqrt[log3^(x^2-x)]' = 0.69*(2x-1) / 2*Sqrt[x^2-x] = 0.345(2x-1)/Sqrt[x^2-x] .

Alon.  

Calculus

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Alon Mandes

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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .

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1. I'm a team member of mathnerds (math site for answering questions) 2. I'm a team member in the Student's Union of the Technion, helping students who have problems in mathematics. 3. 2 years of experience as a math teacher in college. 4. I give free homework help for high school students in Mathematics & Physics. 5. I teach part time in collage the subjects : "Digital Signal Processing" , "Random Signals & Noise" , "Complex Functions".

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M.A in Mathematics & Bs.c in Electronics.

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