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Question
I'm confused on this question and I have a test tomorrow.
The limit x->infinity of (3x^4)*((sinx)/x) represents an asymptote. What value does it approach and does it ever cross the above value?
We know that sin(x) is always bounded between -1 & 1 . So our function will become :
)
[(3x^4)/x]*(sinx)=(3x^3)*M . Where -1<M<1 ("less or equal"). Therefore, as x moves forwards
toward infinity , the value of the function will alternate between +Inf & -Inf . Here's an
I attached you an image illustrating the above .
Note that the function 3x^3 rises as x goes to INF .
Alon.
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Alon Mandes
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Kind of questions I can answer : Limits, Derivatives, Integration, Implicit functions, continuousity, differentiation ,Extremum problems, Lagrange multipliers, Gradients, Surface integrals, Multi variables functions ,Multi variables Integrals,Complex variables ,Complex functions, Curves, Trajectory integrals & Vector analyse,Divergence,Rotor & word problems. Kind of question I can't answer : Economics,Combinatorics,infinite series & convergence ,Statistics & Probabilities .
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