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Calculus/maximum area of rectangle inscribed in a triangle

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Question
Give the largest rectangle inscribed in the triangle formed by line y=0. y=x and 3x+y=20 if one side of the rectangle lies on the x-axis

Answer

Drawing
Hello Erwin,
I attached an image that illustrate the drawing of the rectangle inscribed in the triangle.
We know that , the height of the point b will be : 20-3b . Thus, we obtain :
a=20-3b . The area of the rectangle is : S=a*(b-a)=(20-3b)*[b-(20-3b)]=(20-3b)*[b-20+3b]=
(20-3b)*(4b-20)=80b-400-12b²+60b=140b-12b²-400. To obtain maximum, we derive S with respect
to b : S'(b)=140-24b . Now we set the derivative equal zero :
140-24b=0 --> b=5.833 . Let's find a :
a=20-3b=2.5
So, the dimensions of the largest triangle are : 3⅓ X 2½ .

Alon.

Alon Mandes

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