Expert: Paul Klarreich - 11/21/2010

Question
Find the slop of a line tangent to the curve y=3x^2 at the point P(1.5,6.75) by finding the limit of the slopes of the secant lines PQ where Q has x- value 1,1.4,1.49,1.499.
how do you do this  step by step?

Answer
Questioner:   ken
Country:  United States
Category:  Calculus
Private:  No
 
Subject:  differential calculus
Question:  Find the slop of a line tangent to the curve y=3x^2 at the point P(1.5,6.75) by finding the limit of the slopes of the secant lines PQ where Q has x- value 1,1.4,1.49,1.499.
how do you do this  step by step?
.......................................
For each  x- value 1, 1.4, 1.49, 1.499, you compute the slope of the secant line as in the last question.

You will get a sequence of answers which get closer and closer to 9.000.

That is your limit.  If you want to prove it, listen to your teacher next week.