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Calculus/Critical Numbers

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Question
Determine the critical number(s) of the function            f(x)=2xlnx.

Please show all work so that I can understand how you got to the answer.  Thank you for your help.

Answer
Hi Alex,
f(x) = 2x.lnx
We find the derivative using the product rule. The derivative of 2x is 2 and for lnx is 1/x. So,
f'(x) = 2x(1/x) + 2lnx = 2 + 2lnx
The critical number(s) occur when f'(x) = 0, i.e
2 + 2lnx = 0
lnx = -1
x = e^-1 = 1/e
and
f(x) = 2(1/e) . ln(1/e)
= (2/e).(-1)
= -2/e

Regards

Calculus

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