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Calculus/limit
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Question
ple tell me method how to find the limit of trigometri function
If you're looking for the limit as x goes to infinity of a trig function, there is not one
since the trig functions are cyclic.
If you're looking for the limit as x goes to infinity of a trig function over x,
the limit is 0 for sin() and cos(). There is no limit for the other functions.
If you're looking for a limit as x->0 of any function, the limit is the value at 0.
If you're looking for a limit as x->0 of any function over x,
the only ones that exist are sin(x)/x and tan(x)/x.
It is known that the lim(x->0)(sin(x)/x) = 1.
It is also known that the lim(x->0)(tan(x)/x) = lim(x->0)(sin(x)/(x*cos(x))) =
lim(x->0)(sin(x)/x)*lim(x->0)(1/cos(x)) = 1*1 = 1.
If you would like something more specific, I could answer it if asked.
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