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Calculus/Areas by Integration

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Question
My question is as follows:

Evaluate the integral below by interpreting it as area and using formulas from geometry.

(integral from -8 to 8) of 2 times the square root of (64-x^2) dx.

I know the answer is supposed to be 64pi, but I keep getting 100.53, because the shape is a half circle with a radius of 8.
--> (1/2)(pi)(8)^2 = 100.53. Can you help me??

Answer
Questioner:    Leanna
Private: No
Subject:  Areas
Question: My question is as follows:

Evaluate the integral below by interpreting it as area and using formulas from geometry.

(integral from -8 to 8) of 2 times the square root of (64-x^2) dx.

I know the answer is supposed to be 64pi, but I keep getting 100.53, because the shape is a half circle with a radius of 8.

>> Yes, but you have a factor of '2' in there, which makes it the whole circle.  That should take care of it.

--> (1/2)(pi)(8)^2 = 100.53. Can you help me??  

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Paul Klarreich

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All topics in first-year calculus including infinite series, max-min and related rate problems. Also trigonometry and complex numbers, theory of equations, exponential and logarithmic functions. I can also try (but not guarantee) to answer questions on Analysis -- sequences, limits, continuity.

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I taught all mathematics subjects from elementary algebra to differential equations at a two-year college in New York City for 25 years.

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