Calculus/Integrate

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Question
How would I evaluate a definite integral of an absolute trig value function?
Specifically,this one:

2π∫abs(xcos(x))dx

Evaluated from 0 to 90.

Thank You for helping.

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Charles
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Question: How would I evaluate a definite integral of an absolute trig value function?
Specifically,this one:

2π∫abs(xcos(x))dx

Evaluated from 0 to 90.

................................

abs(something) means:

The something when the something is positive or zero.
The opposite of the something (put minus in front) when the something is negative.

So if you are doing it from 0 to pi/2 (Please!  Degrees are for children), that is all nonnegative, so:

2π∫abs(xcos(x))dx = (from 0 to pi/2)

2π∫xcos(x)dx

Now use integration by parts, etc.  

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Paul Klarreich

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All topics in first-year calculus including infinite series, max-min and related rate problems. Also trigonometry and complex numbers, theory of equations, exponential and logarithmic functions. I can also try (but not guarantee) to answer questions on Analysis -- sequences, limits, continuity.

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I taught all mathematics subjects from elementary algebra to differential equations at a two-year college in New York City for 25 years.

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