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Calculus/double integral help

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Question
Use polar coordinates to calculate ∫∫R 1/((x^2 +y^2)^1/2)dA where R is the region inside the cardioid r = 1 + sin θ and above the x-axis.

I know r = ((x^2 +y^2)^1/2) making the equation ∫∫R 1/r drdθ but that's about as far as I've got! Is the upper limit for the inside ∫ '1 + sin θ'? Not sure about the lower limit though. Is it r=1?
And what will be the limits for the outside ∫?

Thanks a lot!

Answer
This is converted to polar coordinates by the function ∫∫ f(x,y) dx dy = ∫∫ r f(r,Θ) dr dΘ.
Note that there is an r in this conversion.

It seems like the limits would be for r to go from 0 to sinΘ, and then Θ to go from 0 to 2π.  

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