Calculus/Calc

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Question
Suppose R is the region in the plane enclosed by y=x^2 and y=4
a)Compute the perimeter P and the area A of R, and then compute the ration q=A/(P^2)
Note by squaring the perimeter the ratio becomes independent of the units chosen to measure the region.
b)Compute this ratio Q=A/(P^2) for these four regions: the region R, a square, a circle, and an equilateral triangle. Draw the figure in increasing order of Q

Answer
First, we need to note that the curves gives x² = 4 as the intersectoin points.
This means x = ±2, so in both cases, y=4.

The perimeter can be found by taking twice the length on one side and adding in 4 for the top.
I believe the length on one side is found by taking ∫√(x² + (x²)²)dx.
That works out to ∫√x²√(1+x²)dx = ∫x√(1+x²)dx.

Let u=1+x², so du = 2 dx, so (1/2)du = dx, and I think that becomes the integral of u/2,
which is u²/4.  Evaluate this from 0 to 2, multiply the answer by 2, add in the 4 for the top,
and you have got the total perimeter P.

To find the area A, integrate x² from 2 downto -2.

Once this is done, A/P² can be computed.

b) For a square, s=side, so area A=s² and perimeter P=4s;
for a circle, area A=πr² and perimeter P=4π; and, finally,
for an equilateral triangle with side s, area A = (s²√3)/4 and perimeter P = 3r.
Given this, you can compute Q = A/P² for a circle, square, and triangle.

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