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Calculus/rate of change problem

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KARAM MAYMOUN wrote at 2013-01-27 02:30:20
since V=(1/3)(PI)(R^2)(H) AND R=H/2

V=(1/3)(PI)R(H)(H/2)^2(H)

SO V=(1/3)(PI)(H^3/4)

DIFFERENTIATE AND YOU WILL GET (DV/DT)= (1/4)(PI)(H)^2 (DH/DT)

THEN YOU PLUG IN 10 FOR H AND 5 FOR (DH/DT)

AND YOU SHOULD GET 125(PI) FT^3/MIN


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