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Question
Four cities are exactly located at the each end of square land with side 1mile. I want to connect four cities by roads in a manare that if is as inexpensive as possible. I am supposed to use optimal values. What can i do now?

Answer
I would draw an X with the roads, having a city at each of the four endpoints on the X.
The length of the two roads added together is √2 miles for each one.
Since there are two, this makes the total of both roads 2√2.

To do this properly, put the cities on a piece of graph paper at (0,0), (1,0), (0,1), and (1,1).
Put the point that all cities have a road to at some point (x.y) in the middle of the square with the cities.  The distance to the cities is
L(x,y) = √(x² + y²) + √((1-x)² + y²) + √(x² + (1-y)²) + √((1-x)² + (1-y)²).

Trying to take the derivative of that with respect to x or y seems rather complicated to me.
What I would do would be to put x=0.5, y=0.5 into the equation L(x,y) and get the answer.
Then see what L(x,y) gives at (0.49,0.5) and (0.51,5).
It will be found that L(x,y) increases to get to each of these values.
That same can be said about varying y, for x and y in the equation look the same.
In can then be seen the if more than one of the variables is varied, the solution is increased all the more.  From here, it can be said the maximum is at (0.5,0.5).

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Any kind of calculus question you want. I also have answered some questions in Physics (mass, momentum, falling bodies), Chemistry (charge, reactions, symbols, molecules), and Biology.

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